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# Apr 23 Discussions .

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Q1: The swaying time of a mass on a spring is identified with the mass and spring steady by:. A)C) B)D). The swaying time of a mass on a spring is identified with the mass and spring steady by:. A)C) B)D). Higher mass ought to moderate the motions and expand the period. Higher k ought to speed the wavering rate and decline the period. .
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Slide 1

﻿Apr 23 Discussions Spring scale in space Designing a pendulum clock

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Q1: The swaying time of a mass on a spring is identified with the mass and spring steady by: A) C) B) D)

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The wavering time of a mass on a spring is identified with the mass and spring consistent by: A) C) B) D) Higher mass ought to moderate the motions and increment the period. Higher k ought to speed the swaying rate and decline the period.

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P1: Springs in Space Working for NASA, you are entrusted with planning a scale that will work in space. You recollect that a standard scale that measures weight won\'t work, then you review that a mass on a spring will waver at a recurrence that relies on upon the mass (and the spring steady). What spring steady would it be advisable for you to pick so that a 1.0 kg mass has a swaying time of 1.0 second? What might the period be for a 10.0 kg mass wavering on that spring?

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Springs in Space-2 Recall that the time of a mass on a spring is: Therefore, the spring consistent that will give a specific period is: For a 10 kg mass, the period will be

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Q2:The time of a pendulum depends (principally) on… A) the length B) the mass C) the abundancy of the swing D) these

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Q2:The time of a pendulum depends (basically) on… A) the length B) the mass C) the adequacy of the swing D) these (Not on mass; for little amplitudes, the period does not change in particular).

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P2: Pendulum Ponder You are planning an old-school pendulum clock that relies on upon the general motions of a pendulum to keep time. Your pendulum length will be set with the goal that it finishes the tick in one moment and the tock in one moment (that is the period must be two seconds). A) What length ought to the pendulum be (expecting g=9.80 m/s 2 )? B) Suppose you need your pendulum time to work at different areas on Earth. Since the nearby estimation of g shifts by ±0.02 m/s 2 (its lower close to the equator and at hight elevation, higher close to the shafts), the length of the pendulum must be flexible. What amount of change do you have to consider in the length of your pendulum?

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Pendulum Ponder-2 A) the period relies on upon g and the length by: B) Note that the length is corresponding to the estimation of g. Subsequently, if g can shift by ±0.2%, the length must be tunable to a similar degree: ±0.2% of 1 meter is ±2 mm (not an irrelevant sum! On the off chance that you didn\'t consider it, your clock could keep running up to ±0.2% off, or about ±2.9 minutes every day).

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Q3: The speed of a wave on a rope relies on upon the greater part of the accompanying with the exception of: A) gravitational quickening g B) the aggregate mass of the rope C) the strain in rope D) the length of the rope

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Q3: The speed of a wave on a rope relies on upon the majority of the accompanying aside from: A) gravitational increasing speed g Formula for speed of a wave on a rope:

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P3: Waves on a Gondola Ride A ski gondola is associated with the highest point of a slope by a steel link of length 620 m and width 1.5 cm. As the gondola arrives at the finish of its run, it catchs the terminal and sends a wave beat along the link. It is watched that it took 16 s for the beat to return. ( a ) What is the speed of the beat? ( b ) What is the pressure in the link? Data: The thickness of steel is 7800kg/m 3 .

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The speed is given by the aggregate separation crossed, which is double the length of the link, isolated when. What is m/L ? (b) Use m =(Volume)  =  r 2 L   m/L =  r 2  = (0.0075m) 2 (7.8×10 3 kg/m 3 ) = 1.38kg/m So F T =( 1.38kg/m)(77.5m/s) 2 =8289N

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